-3(7x+3)-8x=3x-4(1-8x)

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Solution for -3(7x+3)-8x=3x-4(1-8x) equation: 



-3(7x+3)-8x=3x-4(1-8x)

We move all terms to the left:

-3(7x+3)-8x-(3x-4(1-8x))=0

We add all the numbers together, and all the variables

-3(7x+3)-8x-(3x-4(-8x+1))=0

We add all the numbers together, and all the variables

-8x-3(7x+3)-(3x-4(-8x+1))=0

We multiply parentheses

-8x-21x-(3x-4(-8x+1))-9=0



We calculate terms in parentheses: -(3x-4(-8x+1)), so:

3x-4(-8x+1)

We multiply parentheses

3x+32x-4

We add all the numbers together, and all the variables

35x-4

Back to the equation:

-(35x-4)



We add all the numbers together, and all the variables

-29x-(35x-4)-9=0

We get rid of parentheses

-29x-35x+4-9=0

We add all the numbers together, and all the variables

-64x-5=0

We move all terms containing x to the left, all other terms to the right

-64x=5

x=5/-64

x=-5/64

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