-3(6y-7)+9y=7(y+5)

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Solution for -3(6y-7)+9y=7(y+5) equation: 



-3(6y-7)+9y=7(y+5)

We move all terms to the left:

-3(6y-7)+9y-(7(y+5))=0

We add all the numbers together, and all the variables

9y-3(6y-7)-(7(y+5))=0

We multiply parentheses

9y-18y-(7(y+5))+21=0



We calculate terms in parentheses: -(7(y+5)), so:

7(y+5)

We multiply parentheses

7y+35

Back to the equation:

-(7y+35)



We add all the numbers together, and all the variables

-9y-(7y+35)+21=0

We get rid of parentheses

-9y-7y-35+21=0

We add all the numbers together, and all the variables

-16y-14=0

We move all terms containing y to the left, all other terms to the right

-16y=14

y=14/-16

y=-7/8

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