-3(6u-1)+7u=5(u+3)

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Solution for -3(6u-1)+7u=5(u+3) equation: 



-3(6u-1)+7u=5(u+3)

We move all terms to the left:

-3(6u-1)+7u-(5(u+3))=0

We add all the numbers together, and all the variables

7u-3(6u-1)-(5(u+3))=0

We multiply parentheses

7u-18u-(5(u+3))+3=0



We calculate terms in parentheses: -(5(u+3)), so:

5(u+3)

We multiply parentheses

5u+15

Back to the equation:

-(5u+15)



We add all the numbers together, and all the variables

-11u-(5u+15)+3=0

We get rid of parentheses

-11u-5u-15+3=0

We add all the numbers together, and all the variables

-16u-12=0

We move all terms containing u to the left, all other terms to the right

-16u=12

u=12/-16

u=-3/4

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