-3(6-2x)+23=4-(1)/(3)(-18x-3)

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Solution for -3(6-2x)+23=4-(1)/(3)(-18x-3) equation: 



-3(6-2x)+23=4-(1)/(3)(-18x-3)

We move all terms to the left:

-3(6-2x)+23-(4-(1)/(3)(-18x-3))=0



Domain of the equation: 3(-18x-3))!=0

x∈R



We add all the numbers together, and all the variables

-3(-2x+6)-(4-1/3(-18x-3))+23=0

We multiply parentheses

6x-(4-1/3(-18x-3))-18+23=0

We multiply all the terms by the denominator


6x*3(-18x-3))-(4-18*3(-18x-3))+23*3(-18x-1-3))=0

We add all the numbers together, and all the variables

6x*3(-18x-3))-(4-18*3(-18x-3))+23*3(-18x-4))=0

We add all the numbers together, and all the variables

-18x+6x*3(-18x-3))-(4-18*3(-18x-3))+23*3(=0

Wy multiply elements

18x^2(--162x^2(--18x=0

We use the square of the difference formula

18x^2(+162x^2(+18x=0

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