-3(6-2c)+3c=27

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Solution for -3(6-2c)+3c=27 equation: 



-3(6-2c)+3c=27

We move all terms to the left:

-3(6-2c)+3c-(27)=0

We add all the numbers together, and all the variables

-3(-2c+6)+3c-27=0

We add all the numbers together, and all the variables

3c-3(-2c+6)-27=0

We multiply parentheses

3c+6c-18-27=0

We add all the numbers together, and all the variables

9c-45=0

We move all terms containing c to the left, all other terms to the right

9c=45

c=45/9

c=5

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