-3(5y-4)+8y=3(y+8)

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Solution for -3(5y-4)+8y=3(y+8) equation:



-3(5y-4)+8y=3(y+8)
We move all terms to the left:
-3(5y-4)+8y-(3(y+8))=0
We add all the numbers together, and all the variables
8y-3(5y-4)-(3(y+8))=0
We multiply parentheses
8y-15y-(3(y+8))+12=0
We calculate terms in parentheses: -(3(y+8)), so:
3(y+8)
We multiply parentheses
3y+24
Back to the equation:
-(3y+24)
We add all the numbers together, and all the variables
-7y-(3y+24)+12=0
We get rid of parentheses
-7y-3y-24+12=0
We add all the numbers together, and all the variables
-10y-12=0
We move all terms containing y to the left, all other terms to the right
-10y=12
y=12/-10
y=-1+1/5

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