-3(5y-3)+5y=7+2(2y-4)

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Solution for -3(5y-3)+5y=7+2(2y-4) equation: 



-3(5y-3)+5y=7+2(2y-4)

We move all terms to the left:

-3(5y-3)+5y-(7+2(2y-4))=0

We add all the numbers together, and all the variables

5y-3(5y-3)-(7+2(2y-4))=0

We multiply parentheses

5y-15y-(7+2(2y-4))+9=0



We calculate terms in parentheses: -(7+2(2y-4)), so:

7+2(2y-4)

determiningTheFunctionDomain
2(2y-4)+7

We multiply parentheses

4y-8+7

We add all the numbers together, and all the variables

4y-1

Back to the equation:

-(4y-1)



We add all the numbers together, and all the variables

-10y-(4y-1)+9=0

We get rid of parentheses

-10y-4y+1+9=0

We add all the numbers together, and all the variables

-14y+10=0

We move all terms containing y to the left, all other terms to the right

-14y=-10

y=-10/-14

y=5/7

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