-3(5v-2)+9v=6(v+2)

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Solution for -3(5v-2)+9v=6(v+2) equation: 



-3(5v-2)+9v=6(v+2)

We move all terms to the left:

-3(5v-2)+9v-(6(v+2))=0

We add all the numbers together, and all the variables

9v-3(5v-2)-(6(v+2))=0

We multiply parentheses

9v-15v-(6(v+2))+6=0



We calculate terms in parentheses: -(6(v+2)), so:

6(v+2)

We multiply parentheses

6v+12

Back to the equation:

-(6v+12)



We add all the numbers together, and all the variables

-6v-(6v+12)+6=0

We get rid of parentheses

-6v-6v-12+6=0

We add all the numbers together, and all the variables

-12v-6=0

We move all terms containing v to the left, all other terms to the right

-12v=6

v=6/-12

v=-1/2

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