-3(4z+4)=4(-3z-3)

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Solution for -3(4z+4)=4(-3z-3) equation:


Simplifying
-3(4z + 4) = 4(-3z + -3)

Reorder the terms:
-3(4 + 4z) = 4(-3z + -3)
(4 * -3 + 4z * -3) = 4(-3z + -3)
(-12 + -12z) = 4(-3z + -3)

Reorder the terms:
-12 + -12z = 4(-3 + -3z)
-12 + -12z = (-3 * 4 + -3z * 4)
-12 + -12z = (-12 + -12z)

Add '12' to each side of the equation.
-12 + 12 + -12z = -12 + 12 + -12z

Combine like terms: -12 + 12 = 0
0 + -12z = -12 + 12 + -12z
-12z = -12 + 12 + -12z

Combine like terms: -12 + 12 = 0
-12z = 0 + -12z
-12z = -12z

Add '12z' to each side of the equation.
-12z + 12z = -12z + 12z

Combine like terms: -12z + 12z = 0
0 = -12z + 12z

Combine like terms: -12z + 12z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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