-3(4y-2)-y=4(y-3)

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Solution for -3(4y-2)-y=4(y-3) equation: 



-3(4y-2)-y=4(y-3)

We move all terms to the left:

-3(4y-2)-y-(4(y-3))=0

We add all the numbers together, and all the variables

-1y-3(4y-2)-(4(y-3))=0

We multiply parentheses

-1y-12y-(4(y-3))+6=0



We calculate terms in parentheses: -(4(y-3)), so:

4(y-3)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We add all the numbers together, and all the variables

-13y-(4y-12)+6=0

We get rid of parentheses

-13y-4y+12+6=0

We add all the numbers together, and all the variables

-17y+18=0

We move all terms containing y to the left, all other terms to the right

-17y=-18

y=-18/-17

y=1+1/17

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