-3(4y+5)-19=-8(y+5)+4y

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Solution for -3(4y+5)-19=-8(y+5)+4y equation: 



-3(4y+5)-19=-8(y+5)+4y

We move all terms to the left:

-3(4y+5)-19-(-8(y+5)+4y)=0

We multiply parentheses

-12y-(-8(y+5)+4y)-15-19=0



We calculate terms in parentheses: -(-8(y+5)+4y), so:

-8(y+5)+4y

We add all the numbers together, and all the variables

4y-8(y+5)

We multiply parentheses

4y-8y-40

We add all the numbers together, and all the variables

-4y-40

Back to the equation:

-(-4y-40)



We add all the numbers together, and all the variables

-12y-(-4y-40)-34=0

We get rid of parentheses

-12y+4y+40-34=0

We add all the numbers together, and all the variables

-8y+6=0

We move all terms containing y to the left, all other terms to the right

-8y=-6

y=-6/-8

y=3/4

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