-3(4x-3)+8x=6(x+4)

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Solution for -3(4x-3)+8x=6(x+4) equation: 



-3(4x-3)+8x=6(x+4)

We move all terms to the left:

-3(4x-3)+8x-(6(x+4))=0

We add all the numbers together, and all the variables

8x-3(4x-3)-(6(x+4))=0

We multiply parentheses

8x-12x-(6(x+4))+9=0



We calculate terms in parentheses: -(6(x+4)), so:

6(x+4)

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We add all the numbers together, and all the variables

-4x-(6x+24)+9=0

We get rid of parentheses

-4x-6x-24+9=0

We add all the numbers together, and all the variables

-10x-15=0

We move all terms containing x to the left, all other terms to the right

-10x=15

x=15/-10

x=-1+1/2

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