-3(4x-2)+3(x-4)=-10(x-2)

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Solution for -3(4x-2)+3(x-4)=-10(x-2) equation: 



-3(4x-2)+3(x-4)=-10(x-2)

We move all terms to the left:

-3(4x-2)+3(x-4)-(-10(x-2))=0

We multiply parentheses

-12x+3x-(-10(x-2))+6-12=0



We calculate terms in parentheses: -(-10(x-2)), so:

-10(x-2)

We multiply parentheses

-10x+20

Back to the equation:

-(-10x+20)



We add all the numbers together, and all the variables

-9x-(-10x+20)-6=0

We get rid of parentheses

-9x+10x-20-6=0

We add all the numbers together, and all the variables

x-26=0

We move all terms containing x to the left, all other terms to the right

x=26

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