-3(4x+3)+4(6x+1)=431

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Solution for -3(4x+3)+4(6x+1)=431 equation:



-3(4x+3)+4(6x+1)=431
We move all terms to the left:
-3(4x+3)+4(6x+1)-(431)=0
We multiply parentheses
-12x+24x-9+4-431=0
We add all the numbers together, and all the variables
12x-436=0
We move all terms containing x to the left, all other terms to the right
12x=436
x=436/12
x=36+1/3

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