-3(4v-2)+4v=4(v+6)

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Solution for -3(4v-2)+4v=4(v+6) equation: 



-3(4v-2)+4v=4(v+6)

We move all terms to the left:

-3(4v-2)+4v-(4(v+6))=0

We add all the numbers together, and all the variables

4v-3(4v-2)-(4(v+6))=0

We multiply parentheses

4v-12v-(4(v+6))+6=0



We calculate terms in parentheses: -(4(v+6)), so:

4(v+6)

We multiply parentheses

4v+24

Back to the equation:

-(4v+24)



We add all the numbers together, and all the variables

-8v-(4v+24)+6=0

We get rid of parentheses

-8v-4v-24+6=0

We add all the numbers together, and all the variables

-12v-18=0

We move all terms containing v to the left, all other terms to the right

-12v=18

v=18/-12

v=-1+1/2

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