-3(4b-10)=2(-6b+15)

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Solution for -3(4b-10)=2(-6b+15) equation: 



-3(4b-10)=2(-6b+15)

We move all terms to the left:

-3(4b-10)-(2(-6b+15))=0

We multiply parentheses

-12b-(2(-6b+15))+30=0



We calculate terms in parentheses: -(2(-6b+15)), so:

2(-6b+15)

We multiply parentheses

-12b+30

Back to the equation:

-(-12b+30)



We get rid of parentheses

-12b+12b-30+30=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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