-3(4b+2)+(13b-2)=0

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Solution for -3(4b+2)+(13b-2)=0 equation:


Simplifying
-3(4b + 2) + (13b + -2) = 0

Reorder the terms:
-3(2 + 4b) + (13b + -2) = 0
(2 * -3 + 4b * -3) + (13b + -2) = 0
(-6 + -12b) + (13b + -2) = 0

Reorder the terms:
-6 + -12b + (-2 + 13b) = 0

Remove parenthesis around (-2 + 13b)
-6 + -12b + -2 + 13b = 0

Reorder the terms:
-6 + -2 + -12b + 13b = 0

Combine like terms: -6 + -2 = -8
-8 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-8 + 1b = 0

Solving
-8 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1b = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1b = 0 + 8
1b = 0 + 8

Combine like terms: 0 + 8 = 8
1b = 8

Divide each side by '1'.
b = 8

Simplifying
b = 8

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