-3(4b+1)+(13b-3)=0

Solution for -3(4b+1)+(13b-3)=0 equation:

Simplifying
-3(4b + 1) + (13b + -3) = 0

Reorder the terms:
-3(1 + 4b) + (13b + -3) = 0
(1 * -3 + 4b * -3) + (13b + -3) = 0
(-3 + -12b) + (13b + -3) = 0

Reorder the terms:
-3 + -12b + (-3 + 13b) = 0

Remove parenthesis around (-3 + 13b)
-3 + -12b + -3 + 13b = 0

Reorder the terms:
-3 + -3 + -12b + 13b = 0

Combine like terms: -3 + -3 = -6
-6 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-6 + 1b = 0

Solving
-6 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + 1b = 0 + 6

Combine like terms: -6 + 6 = 0
0 + 1b = 0 + 6
1b = 0 + 6

Combine like terms: 0 + 6 = 6
1b = 6

Divide each side by '1'.
b = 6

Simplifying
b = 6