-3(4b+1)+(13b-1)=0

Solution for -3(4b+1)+(13b-1)=0 equation:

Simplifying
-3(4b + 1) + (13b + -1) = 0

Reorder the terms:
-3(1 + 4b) + (13b + -1) = 0
(1 * -3 + 4b * -3) + (13b + -1) = 0
(-3 + -12b) + (13b + -1) = 0

Reorder the terms:
-3 + -12b + (-1 + 13b) = 0

Remove parenthesis around (-1 + 13b)
-3 + -12b + -1 + 13b = 0

Reorder the terms:
-3 + -1 + -12b + 13b = 0

Combine like terms: -3 + -1 = -4
-4 + -12b + 13b = 0

Combine like terms: -12b + 13b = 1b
-4 + 1b = 0

Solving
-4 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 1b = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 1b = 0 + 4
1b = 0 + 4

Combine like terms: 0 + 4 = 4
1b = 4

Divide each side by '1'.
b = 4

Simplifying
b = 4