-3(4-3x)9x=12

Solution for -3(4-3x)9x=12 equation:

-3(4-3x)9x=12

We move all terms to the left:

-3(4-3x)9x-(12)=0

We add all the numbers together, and all the variables

-3(-3x+4)9x-12=0

We multiply parentheses

81x^2-108x-12=0

a = 81; b = -108; c = -12;
Δ = b2-4ac
Δ = -1082-4·81·(-12)
Δ = 15552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15552}=\sqrt{5184*3}=\sqrt{5184}*\sqrt{3}=72\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-72\sqrt{3}}{2*81}=\frac{108-72\sqrt{3}}{162}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+72\sqrt{3}}{2*81}=\frac{108+72\sqrt{3}}{162}
$