-3(3y+3)-17=-6y+6)+3y

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Solution for -3(3y+3)-17=-6y+6)+3y equation: 



-3(3y+3)-17=-6y+6)+3y

We move all terms to the left:

-3(3y+3)-17-(-6y+6)+3y)=0

We multiply parentheses

-9y-(-6y+6)+3y)-17-9=0

We get rid of parentheses

-9y+6y+3y)-17-9-6=0

We add all the numbers together, and all the variables

-3y+3y)-17-9-6=0

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