-3(3x-2)+7(x+3)=6+3x-8x

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Solution for -3(3x-2)+7(x+3)=6+3x-8x equation: 



-3(3x-2)+7(x+3)=6+3x-8x

We move all terms to the left:

-3(3x-2)+7(x+3)-(6+3x-8x)=0

We add all the numbers together, and all the variables

-3(3x-2)+7(x+3)-(-5x+6)=0

We multiply parentheses

-9x+7x-(-5x+6)+6+21=0

We get rid of parentheses

-9x+7x+5x-6+6+21=0

We add all the numbers together, and all the variables

3x+21=0

We move all terms containing x to the left, all other terms to the right

3x=-21

x=-21/3

x=-7

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