-3(3v-2)+3v=2(v+1)

Solution for -3(3v-2)+3v=2(v+1) equation:

-3(3v-2)+3v=2(v+1)

We move all terms to the left:

-3(3v-2)+3v-(2(v+1))=0

We add all the numbers together, and all the variables

3v-3(3v-2)-(2(v+1))=0

We multiply parentheses

3v-9v-(2(v+1))+6=0


We calculate terms in parentheses: -(2(v+1)), so:

2(v+1)

We multiply parentheses

2v+2

Back to the equation:

-(2v+2)


We add all the numbers together, and all the variables

-6v-(2v+2)+6=0

We get rid of parentheses

-6v-2v-2+6=0

We add all the numbers together, and all the variables

-8v+4=0

We move all terms containing v to the left, all other terms to the right

-8v=-4

v=-4/-8

v=1/2