-3(3c+15)=2(10-c)

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Solution for -3(3c+15)=2(10-c) equation:



-3(3c+15)=2(10-c)
We move all terms to the left:
-3(3c+15)-(2(10-c))=0
We add all the numbers together, and all the variables
-3(3c+15)-(2(-1c+10))=0
We multiply parentheses
-9c-(2(-1c+10))-45=0
We calculate terms in parentheses: -(2(-1c+10)), so:
2(-1c+10)
We multiply parentheses
-2c+20
Back to the equation:
-(-2c+20)
We get rid of parentheses
-9c+2c-20-45=0
We add all the numbers together, and all the variables
-7c-65=0
We move all terms containing c to the left, all other terms to the right
-7c=65
c=65/-7
c=-9+2/7

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