-3(3b+4)+(10b-8)=0

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Solution for -3(3b+4)+(10b-8)=0 equation:


Simplifying
-3(3b + 4) + (10b + -8) = 0

Reorder the terms:
-3(4 + 3b) + (10b + -8) = 0
(4 * -3 + 3b * -3) + (10b + -8) = 0
(-12 + -9b) + (10b + -8) = 0

Reorder the terms:
-12 + -9b + (-8 + 10b) = 0

Remove parenthesis around (-8 + 10b)
-12 + -9b + -8 + 10b = 0

Reorder the terms:
-12 + -8 + -9b + 10b = 0

Combine like terms: -12 + -8 = -20
-20 + -9b + 10b = 0

Combine like terms: -9b + 10b = 1b
-20 + 1b = 0

Solving
-20 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 1b = 0 + 20

Combine like terms: -20 + 20 = 0
0 + 1b = 0 + 20
1b = 0 + 20

Combine like terms: 0 + 20 = 20
1b = 20

Divide each side by '1'.
b = 20

Simplifying
b = 20

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