-3(3b+2)+(10b-6)=0

Solution for -3(3b+2)+(10b-6)=0 equation:

Simplifying
-3(3b + 2) + (10b + -6) = 0

Reorder the terms:
-3(2 + 3b) + (10b + -6) = 0
(2 * -3 + 3b * -3) + (10b + -6) = 0
(-6 + -9b) + (10b + -6) = 0

Reorder the terms:
-6 + -9b + (-6 + 10b) = 0

Remove parenthesis around (-6 + 10b)
-6 + -9b + -6 + 10b = 0

Reorder the terms:
-6 + -6 + -9b + 10b = 0

Combine like terms: -6 + -6 = -12
-12 + -9b + 10b = 0

Combine like terms: -9b + 10b = 1b
-12 + 1b = 0

Solving
-12 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 1b = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 1b = 0 + 12
1b = 0 + 12

Combine like terms: 0 + 12 = 12
1b = 12

Divide each side by '1'.
b = 12

Simplifying
b = 12