-3(3-x)+2x=4(x-4)-6

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Solution for -3(3-x)+2x=4(x-4)-6 equation: 



-3(3-x)+2x=4(x-4)-6

We move all terms to the left:

-3(3-x)+2x-(4(x-4)-6)=0

We add all the numbers together, and all the variables

-3(-1x+3)+2x-(4(x-4)-6)=0

We add all the numbers together, and all the variables

2x-3(-1x+3)-(4(x-4)-6)=0

We multiply parentheses

2x+3x-(4(x-4)-6)-9=0



We calculate terms in parentheses: -(4(x-4)-6), so:

4(x-4)-6

We multiply parentheses

4x-16-6

We add all the numbers together, and all the variables

4x-22

Back to the equation:

-(4x-22)



We add all the numbers together, and all the variables

5x-(4x-22)-9=0

We get rid of parentheses

5x-4x+22-9=0

We add all the numbers together, and all the variables

x+13=0

We move all terms containing x to the left, all other terms to the right

x=-13

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