-3(3-2x)=2(x+3)+5

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Solution for -3(3-2x)=2(x+3)+5 equation: 



-3(3-2x)=2(x+3)+5

We move all terms to the left:

-3(3-2x)-(2(x+3)+5)=0

We add all the numbers together, and all the variables

-3(-2x+3)-(2(x+3)+5)=0

We multiply parentheses

6x-(2(x+3)+5)-9=0



We calculate terms in parentheses: -(2(x+3)+5), so:

2(x+3)+5

We multiply parentheses

2x+6+5

We add all the numbers together, and all the variables

2x+11

Back to the equation:

-(2x+11)



We get rid of parentheses

6x-2x-11-9=0

We add all the numbers together, and all the variables

4x-20=0

We move all terms containing x to the left, all other terms to the right

4x=20

x=20/4

x=5

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