-3(2y-7)-y=3(y-2)

Solution for -3(2y-7)-y=3(y-2) equation:

-3(2y-7)-y=3(y-2)

We move all terms to the left:

-3(2y-7)-y-(3(y-2))=0

We add all the numbers together, and all the variables

-1y-3(2y-7)-(3(y-2))=0

We multiply parentheses

-1y-6y-(3(y-2))+21=0


We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)


We add all the numbers together, and all the variables

-7y-(3y-6)+21=0

We get rid of parentheses

-7y-3y+6+21=0

We add all the numbers together, and all the variables

-10y+27=0

We move all terms containing y to the left, all other terms to the right

-10y=-27

y=-27/-10

y=2+7/10