-3(2y-6)=-6(y-2)+6

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Solution for -3(2y-6)=-6(y-2)+6 equation:


Simplifying
-3(2y + -6) = -6(y + -2) + 6

Reorder the terms:
-3(-6 + 2y) = -6(y + -2) + 6
(-6 * -3 + 2y * -3) = -6(y + -2) + 6
(18 + -6y) = -6(y + -2) + 6

Reorder the terms:
18 + -6y = -6(-2 + y) + 6
18 + -6y = (-2 * -6 + y * -6) + 6
18 + -6y = (12 + -6y) + 6

Reorder the terms:
18 + -6y = 12 + 6 + -6y

Combine like terms: 12 + 6 = 18
18 + -6y = 18 + -6y

Add '-18' to each side of the equation.
18 + -18 + -6y = 18 + -18 + -6y

Combine like terms: 18 + -18 = 0
0 + -6y = 18 + -18 + -6y
-6y = 18 + -18 + -6y

Combine like terms: 18 + -18 = 0
-6y = 0 + -6y
-6y = -6y

Add '6y' to each side of the equation.
-6y + 6y = -6y + 6y

Combine like terms: -6y + 6y = 0
0 = -6y + 6y

Combine like terms: -6y + 6y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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