-3(2y-2)-y=-4(y-4)

Solution for -3(2y-2)-y=-4(y-4) equation:

-3(2y-2)-y=-4(y-4)

We move all terms to the left:

-3(2y-2)-y-(-4(y-4))=0

We add all the numbers together, and all the variables

-1y-3(2y-2)-(-4(y-4))=0

We multiply parentheses

-1y-6y-(-4(y-4))+6=0


We calculate terms in parentheses: -(-4(y-4)), so:

-4(y-4)

We multiply parentheses

-4y+16

Back to the equation:

-(-4y+16)


We add all the numbers together, and all the variables

-7y-(-4y+16)+6=0

We get rid of parentheses

-7y+4y-16+6=0

We add all the numbers together, and all the variables

-3y-10=0

We move all terms containing y to the left, all other terms to the right

-3y=10

y=10/-3

y=-3+1/3