-3(2y-10)-y=-2(y-4)

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Solution for -3(2y-10)-y=-2(y-4) equation: 



-3(2y-10)-y=-2(y-4)

We move all terms to the left:

-3(2y-10)-y-(-2(y-4))=0

We add all the numbers together, and all the variables

-1y-3(2y-10)-(-2(y-4))=0

We multiply parentheses

-1y-6y-(-2(y-4))+30=0



We calculate terms in parentheses: -(-2(y-4)), so:

-2(y-4)

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We add all the numbers together, and all the variables

-7y-(-2y+8)+30=0

We get rid of parentheses

-7y+2y-8+30=0

We add all the numbers together, and all the variables

-5y+22=0

We move all terms containing y to the left, all other terms to the right

-5y=-22

y=-22/-5

y=4+2/5

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