-3(2y)+3y=2(3y-3)

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Solution for -3(2y)+3y=2(3y-3) equation: 



-3(2y)+3y=2(3y-3)

We move all terms to the left:

-3(2y)+3y-(2(3y-3))=0

We add all the numbers together, and all the variables

-29y-(2(3y-3))=0



We calculate terms in parentheses: -(2(3y-3)), so:

2(3y-3)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We get rid of parentheses

-29y-6y+6=0

We add all the numbers together, and all the variables

-35y+6=0

We move all terms containing y to the left, all other terms to the right

-35y=-6

y=-6/-35

y=6/35

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