-3(2x-3)+2=(-x+10)

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Solution for -3(2x-3)+2=(-x+10) equation: 



-3(2x-3)+2=(-x+10)

We move all terms to the left:

-3(2x-3)+2-((-x+10))=0

We add all the numbers together, and all the variables

-3(2x-3)-((-1x+10))+2=0

We multiply parentheses

-6x-((-1x+10))+9+2=0



We calculate terms in parentheses: -((-1x+10)), so:

(-1x+10)

We get rid of parentheses

-1x+10

Back to the equation:

-(-1x+10)



We add all the numbers together, and all the variables

-6x-(-1x+10)+11=0

We get rid of parentheses

-6x+1x-10+11=0

We add all the numbers together, and all the variables

-5x+1=0

We move all terms containing x to the left, all other terms to the right

-5x=-1

x=-1/-5

x=1/5

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