-3(2x-2)=3(x+4)+3

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Solution for -3(2x-2)=3(x+4)+3 equation: 



-3(2x-2)=3(x+4)+3

We move all terms to the left:

-3(2x-2)-(3(x+4)+3)=0

We multiply parentheses

-6x-(3(x+4)+3)+6=0



We calculate terms in parentheses: -(3(x+4)+3), so:

3(x+4)+3

We multiply parentheses

3x+12+3

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

-6x-3x-15+6=0

We add all the numbers together, and all the variables

-9x-9=0

We move all terms containing x to the left, all other terms to the right

-9x=9

x=9/-9

x=-1

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