-3(2x-10)+7x=20

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Solution for -3(2x-10)+7x=20 equation:



-3(2x-10)+7x=20
We move all terms to the left:
-3(2x-10)+7x-(20)=0
We add all the numbers together, and all the variables
7x-3(2x-10)-20=0
We multiply parentheses
7x-6x+30-20=0
We add all the numbers together, and all the variables
x+10=0
We move all terms containing x to the left, all other terms to the right
x=-10

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