-3(2x-1)-8=-6(x-2)+11x

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Solution for -3(2x-1)-8=-6(x-2)+11x equation: 



-3(2x-1)-8=-6(x-2)+11x

We move all terms to the left:

-3(2x-1)-8-(-6(x-2)+11x)=0

We multiply parentheses

-6x-(-6(x-2)+11x)+3-8=0



We calculate terms in parentheses: -(-6(x-2)+11x), so:

-6(x-2)+11x

We add all the numbers together, and all the variables

11x-6(x-2)

We multiply parentheses

11x-6x+12

We add all the numbers together, and all the variables

5x+12

Back to the equation:

-(5x+12)



We add all the numbers together, and all the variables

-6x-(5x+12)-5=0

We get rid of parentheses

-6x-5x-12-5=0

We add all the numbers together, and all the variables

-11x-17=0

We move all terms containing x to the left, all other terms to the right

-11x=17

x=17/-11

x=-1+6/11

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