-3(2x+4)=4(3x-2)+8

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Solution for -3(2x+4)=4(3x-2)+8 equation: 



-3(2x+4)=4(3x-2)+8

We move all terms to the left:

-3(2x+4)-(4(3x-2)+8)=0

We multiply parentheses

-6x-(4(3x-2)+8)-12=0



We calculate terms in parentheses: -(4(3x-2)+8), so:

4(3x-2)+8

We multiply parentheses

12x-8+8

We add all the numbers together, and all the variables

12x

Back to the equation:

-(12x)



We add all the numbers together, and all the variables

-18x-12=0

We move all terms containing x to the left, all other terms to the right

-18x=12

x=12/-18

x=-2/3

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