-3(2x+4)-10=22-4(5+2x)-4

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Solution for -3(2x+4)-10=22-4(5+2x)-4 equation: 



-3(2x+4)-10=22-4(5+2x)-4

We move all terms to the left:

-3(2x+4)-10-(22-4(5+2x)-4)=0

We add all the numbers together, and all the variables

-3(2x+4)-(22-4(2x+5)-4)-10=0

We multiply parentheses

-6x-(22-4(2x+5)-4)-12-10=0



We calculate terms in parentheses: -(22-4(2x+5)-4), so:

22-4(2x+5)-4

determiningTheFunctionDomain
-4(2x+5)+22-4

We add all the numbers together, and all the variables

-4(2x+5)+18

We multiply parentheses

-8x-20+18

We add all the numbers together, and all the variables

-8x-2

Back to the equation:

-(-8x-2)



We add all the numbers together, and all the variables

-6x-(-8x-2)-22=0

We get rid of parentheses

-6x+8x+2-22=0

We add all the numbers together, and all the variables

2x-20=0

We move all terms containing x to the left, all other terms to the right

2x=20

x=20/2

x=10

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