-3(2x+12)=3x-7/2

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Solution for -3(2x+12)=3x-7/2 equation: 



-3(2x+12)=3x-7/2

We move all terms to the left:

-3(2x+12)-(3x-7/2)=0

We add all the numbers together, and all the variables

-3(2x+12)-(+3x-7/2)=0

We multiply parentheses

-6x-(+3x-7/2)-36=0

We get rid of parentheses

-6x-3x-36+7/2=0

We multiply all the terms by the denominator


-6x*2-3x*2+7-36*2=0

We add all the numbers together, and all the variables

-6x*2-3x*2-65=0

Wy multiply elements

-12x-6x-65=0

We add all the numbers together, and all the variables

-18x-65=0

We move all terms containing x to the left, all other terms to the right

-18x=65

x=65/-18

x=-3+11/18

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