-3(2v-3)+3v=7(v+1)

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Solution for -3(2v-3)+3v=7(v+1) equation: 



-3(2v-3)+3v=7(v+1)

We move all terms to the left:

-3(2v-3)+3v-(7(v+1))=0

We add all the numbers together, and all the variables

3v-3(2v-3)-(7(v+1))=0

We multiply parentheses

3v-6v-(7(v+1))+9=0



We calculate terms in parentheses: -(7(v+1)), so:

7(v+1)

We multiply parentheses

7v+7

Back to the equation:

-(7v+7)



We add all the numbers together, and all the variables

-3v-(7v+7)+9=0

We get rid of parentheses

-3v-7v-7+9=0

We add all the numbers together, and all the variables

-10v+2=0

We move all terms containing v to the left, all other terms to the right

-10v=-2

v=-2/-10

v=1/5

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