-3(2t-5)+2t=8t-2

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Solution for -3(2t-5)+2t=8t-2 equation: 



-3(2t-5)+2t=8t-2

We move all terms to the left:

-3(2t-5)+2t-(8t-2)=0

We add all the numbers together, and all the variables

2t-3(2t-5)-(8t-2)=0

We multiply parentheses

2t-6t-(8t-2)+15=0

We get rid of parentheses

2t-6t-8t+2+15=0

We add all the numbers together, and all the variables

-12t+17=0

We move all terms containing t to the left, all other terms to the right

-12t=-17

t=-17/-12

t=1+5/12

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