-3(2s-6)-18=2(8s+9)-3

Solution for -3(2s-6)-18=2(8s+9)-3 equation:

-3(2s-6)-18=2(8s+9)-3

We move all terms to the left:

-3(2s-6)-18-(2(8s+9)-3)=0

We multiply parentheses

-6s-(2(8s+9)-3)+18-18=0


We calculate terms in parentheses: -(2(8s+9)-3), so:

2(8s+9)-3

We multiply parentheses

16s+18-3

We add all the numbers together, and all the variables

16s+15

Back to the equation:

-(16s+15)


We add all the numbers together, and all the variables

-6s-(16s+15)=0

We get rid of parentheses

-6s-16s-15=0

We add all the numbers together, and all the variables

-22s-15=0

We move all terms containing s to the left, all other terms to the right

-22s=15

s=15/-22

s=-15/22