-3(2s-3)-9=-3(9s+5)-5

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Solution for -3(2s-3)-9=-3(9s+5)-5 equation: 



-3(2s-3)-9=-3(9s+5)-5

We move all terms to the left:

-3(2s-3)-9-(-3(9s+5)-5)=0

We multiply parentheses

-6s-(-3(9s+5)-5)+9-9=0



We calculate terms in parentheses: -(-3(9s+5)-5), so:

-3(9s+5)-5

We multiply parentheses

-27s-15-5

We add all the numbers together, and all the variables

-27s-20

Back to the equation:

-(-27s-20)



We add all the numbers together, and all the variables

-6s-(-27s-20)=0

We get rid of parentheses

-6s+27s+20=0

We add all the numbers together, and all the variables

21s+20=0

We move all terms containing s to the left, all other terms to the right

21s=-20

s=-20/21

s=-20/21

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