-3(2r+5)+5=4r-7(2r-2)

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Solution for -3(2r+5)+5=4r-7(2r-2) equation: 



-3(2r+5)+5=4r-7(2r-2)

We move all terms to the left:

-3(2r+5)+5-(4r-7(2r-2))=0

We multiply parentheses

-6r-(4r-7(2r-2))-15+5=0



We calculate terms in parentheses: -(4r-7(2r-2)), so:

4r-7(2r-2)

We multiply parentheses

4r-14r+14

We add all the numbers together, and all the variables

-10r+14

Back to the equation:

-(-10r+14)



We add all the numbers together, and all the variables

-6r-(-10r+14)-10=0

We get rid of parentheses

-6r+10r-14-10=0

We add all the numbers together, and all the variables

4r-24=0

We move all terms containing r to the left, all other terms to the right

4r=24

r=24/4

r=6

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