-3(2q-8)+10q=16

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Solution for -3(2q-8)+10q=16 equation: 



-3(2q-8)+10q=16

We move all terms to the left:

-3(2q-8)+10q-(16)=0

We add all the numbers together, and all the variables

10q-3(2q-8)-16=0

We multiply parentheses

10q-6q+24-16=0

We add all the numbers together, and all the variables

4q+8=0

We move all terms containing q to the left, all other terms to the right

4q=-8

q=-8/4

q=-2

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