-3(2k-9)=3(k-12)

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Solution for -3(2k-9)=3(k-12) equation: 



-3(2k-9)=3(k-12)

We move all terms to the left:

-3(2k-9)-(3(k-12))=0

We multiply parentheses

-6k-(3(k-12))+27=0



We calculate terms in parentheses: -(3(k-12)), so:

3(k-12)

We multiply parentheses

3k-36

Back to the equation:

-(3k-36)



We get rid of parentheses

-6k-3k+36+27=0

We add all the numbers together, and all the variables

-9k+63=0

We move all terms containing k to the left, all other terms to the right

-9k=-63

k=-63/-9

k=+7

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