-3(2b+1)+(7b-2)=2

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Solution for -3(2b+1)+(7b-2)=2 equation:


Simplifying
-3(2b + 1) + (7b + -2) = 2

Reorder the terms:
-3(1 + 2b) + (7b + -2) = 2
(1 * -3 + 2b * -3) + (7b + -2) = 2
(-3 + -6b) + (7b + -2) = 2

Reorder the terms:
-3 + -6b + (-2 + 7b) = 2

Remove parenthesis around (-2 + 7b)
-3 + -6b + -2 + 7b = 2

Reorder the terms:
-3 + -2 + -6b + 7b = 2

Combine like terms: -3 + -2 = -5
-5 + -6b + 7b = 2

Combine like terms: -6b + 7b = 1b
-5 + 1b = 2

Solving
-5 + 1b = 2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 1b = 2 + 5

Combine like terms: -5 + 5 = 0
0 + 1b = 2 + 5
1b = 2 + 5

Combine like terms: 2 + 5 = 7
1b = 7

Divide each side by '1'.
b = 7

Simplifying
b = 7

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