-3(1y+2)=6

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Solution for -3(1y+2)=6 equation:



-3(1y+2)=6
We move all terms to the left:
-3(1y+2)-(6)=0
We add all the numbers together, and all the variables
-3(y+2)-6=0
We multiply parentheses
-3y-6-6=0
We add all the numbers together, and all the variables
-3y-12=0
We move all terms containing y to the left, all other terms to the right
-3y=12
y=12/-3
y=-4

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