-3(1x-1)+8(1x-3)=6x+7-5

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Solution for -3(1x-1)+8(1x-3)=6x+7-5 equation: 



-3(1x-1)+8(1x-3)=6x+7-5

We move all terms to the left:

-3(1x-1)+8(1x-3)-(6x+7-5)=0

We add all the numbers together, and all the variables

-3(x-1)+8(x-3)-(6x+2)=0

We multiply parentheses

-3x+8x-(6x+2)+3-24=0

We get rid of parentheses

-3x+8x-6x-2+3-24=0

We add all the numbers together, and all the variables

-1x-23=0

We move all terms containing x to the left, all other terms to the right

-x=23

x=23/-1

x=-23

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